Calculation of estimates for the construction of a brick house

Brick building in Russia confidently holds its position. After all, this wall material is one of the best in terms of wear resistance, inertness to water and cold, aggressive environments and combustion. At the same time, the level of thermal conductivity of a brick block is quite satisfactory for a modern developer. Therefore, in the material we will figure out how to correctly draw up an estimate for the construction of a brick house.

It is worth remembering that the estimate documentation allows not only to determine the approximate amount of construction costs, but also to exercise control over the injection of funds into the performance of work. After all, it is not always advisable to stop at a certain stage of construction due to lack of money.

The main sections of the estimate

Any estimate documentation should be as detailed as possible in order to exclude possible incidents and downtime during the construction of a house. So, the content of the estimate for a brick house should include the following sections:

• Soil preparation costs. If the site is not ready for construction, it will have to be cleared and the top fertile soil layer removed in order to save the land for planting garden crops or ornamental plants. This expense item includes the rental of special equipment, if necessary.
• The cost of building a foundation for a house. It is known that under a brick building it is necessary to make a monolithic strip or slab foundation. And the higher the house is, the deeper and wider the basis should be. So, for a two-story brick house, it is better to make a slab foundation or de foundation more than a meter deep.
• Funding for wall extrusion. This includes the cost of the wall material in the required amount and adds to the amount the cost of the solution and the possible work of specialists.
• Ceiling installation of concrete slabs. As a rule, for these purposes they rent special equipment that will lift slab floors. This item of expenditure should not be forgotten in addition to the cost of the concrete products themselves.
• Roof installation costs, including the price of roofing material, rafter timber, batten boards and waterproofing insulation. Also, do not forget about accessories and fasteners.
• The cost of window and door blocks for the house, as well as their installation.
• Financing the installation of all communications, such as water supply, sewerage, electricity.
• Interior decoration. This expense item will help you deduce the total amount needed for the installation of the building. And although this amount is approximate, it will still be close to the expected result.

Tip: do not forget to include in the estimate the transport costs for the delivery of building materials, as well as the cost of the work of invited craftsmen.

Foundation calculations

Since everything is clear with the items of the estimate for cleaning and preparing the site, and the calculations for the foundation and wall material are more confused, we will consider these aspects of the estimate documentation. We will derive calculations using the example of a one-story brick house with sides of 10x10 m. Having understood the principles of performing mathematical operations, you will be able to independently draw up an estimate in the future for any other type of building.

So, the estimate for the foundation device should include the following items:

• Digging a trench for tape or slab. The latter option is especially relevant, because if you dig a trench on your own, it’s still at least somehow possible, then digging a foundation pit for a monolith will have to be a bit long. So it is better to use an excavator, which will have to be paid at the rate of rent / hour.
• Then it is necessary to include the formwork device in the expense item. Moreover, both the performance of the work itself and the cost of the material that will be needed to fill the tape. As a material, a cutting board is used. To calculate its quantity, it is necessary to find out the length of the entire basis. And these are 4 walls of 10 meters, plus all internal partitions. Imagine that the total length of the foundation inside the house will be 18 meters. In total we have (4x10) + 18 = 58 meters of formwork. Now you need to multiply by the height of the base to get the number of boards in m2. For the initial one, we take the foundation with a depth of 1 m and add to it the height of the base 50 cm. In total, we have 1.5 meters of formwork height. 58x1.5=87 m2. And now we multiply the value by 2, since the formwork consists of two walls. In total we get 174 m2 of boards. But lumber is calculated in m3 or pieces. Therefore, the resulting number is multiplied by the thickness of the board, calculated in meters. And if the standard board thickness is 25-30 cm, then you need to multiply by 0.25-0.3 m. So, 174x0.25 = 43.5 m3 of board is needed for formwork. It remains to multiply the result obtained by the price of one m3 of board. And do not forget to include all fasteners in the estimate.
• Now you need to calculate the amount of concrete or consumables for mixing it.

Important: taking into account the fact that it is better to pour the tape at a time in one approach, it is better to buy a ready-made concrete mixture, since it will not be possible to prepare such an amount of the mixture with your own hands. And pouring a tape-type foundation is gradually prohibited by SNiP. Otherwise, the base will be shaky. Therefore, we will consider the estimate using the example of calculating the amount of concrete.

• Everything is simple here, just multiply the total length of the foundation, its height and width. We already have a total length of 58 m. The height of the base, together with the plinth, is 1.5 m. And its width for laying two bricks will be 60 cm (provided that the laying of two bricks has a thickness of 51 cm). So, we multiply 58x1.5x0.60 \u003d 52.2 m3. This is exactly the volume of the finished concrete solution needed to fill the entire tape. Now we multiply the volume by the price of one m3 of finished concrete.

• Armature costs.

Important: SNiP regulates that with a foundation width of more than 40 cm, it is necessary to use reinforcement in six longitudinal rods. That is, three from above and three from below with a step of 20 cm. Otherwise, the solidity and reliability of the basis will be doubtful.

• To simplify the task, you can use the online calculator on the construction portal. But if you gravitate toward mathematics, then we will calculate on our own. It is known that the tape is reinforced in two belts (lower and upper). In this case, the location of the vertical rods should be in increments of 50 cm. Knowing the total length of the foundation, we multiply the number by two (lower and upper belts). 58x2 \u003d 116 m. And now we multiply this number by six (the number of longitudinal strips of reinforcement in two belts. 116x6 \u003d 696 m of longitudinal reinforcement with a section of 12 mm. Now we calculate the footage of rods for vertical knitting of belts. Taking into account the fact that they need to be placed on a distance of 50 cm from each other, we divide the total length of the basis by 0.5 and get 58: 0.5 \u003d 29 m. This is the footage of a vertical rod for one longitudinal knit, and we have three of them. 29x3 \u003d 77 m. And it remains to multiply the resulting value by the height of the rod (1.4 m - the height of the foundation - 5 cm above and 5 cm below the reinforcement recess).Total we have 77x1.4 \u003d 107.8 m of a rod with a cross section of 6-8 mm .

Important: it is desirable to add a coefficient of 0.2 to the stock of the rod to the volumes obtained. And now we multiply the received volumes by the cost per m2. In the estimate, do not forget to include the cost of delivery and the work of a professional who will knit the armature.

Wall material costs

We decided that our outer walls would be made of two bricks. Using the example of the forcing of external walls, we will consider how the calculation of the volume of material is performed. And we already know that the thickness of the wall in two bricks will be equal to 51 cm. The length of our walls is 10m and 10m. The height will conditionally be 2.5 m. At the same time, we have 7 window openings with parameters of 1.2x1.5 m and one door 1x2 m.

Important: you can perform calculations by taking into account the thickness of the seams and without taking into account this parameter. In the first case, the volume of the brick may exceed the real one by 25-30%, but it can be used for a possible battle and laying of internal partitions. In the second case, the calculations will be more accurate, but another 10-15% will have to be added to a possible battle.

The first calculation looks like this:

• We determine the total length of the outer walls - 10x4 = 40 m;
• We calculate the area of ​​\u200b\u200bthe walls, multiplying the length by the height - 40x2.5 \u003d 100 m2;
• We calculate the total area of ​​​​all window and door openings - (1x2) + (1.2x1.5)x7 \u003d 14.6 m2;
• Now, from the total area of ​​\u200b\u200bthe walls, we subtract the area of ​​the openings - 100-14.6 \u003d 85.4 m2 of clean brickwork along the outer wall.
• Now we derive the number of bricks per square meter of masonry. To do this, we determine the area of ​​​​its end: 0.12 * 0.065 \u003d 0.0078. It remains to divide the resulting value by one: 1/0.0078=128. We multiply the result by two (laying in 2 bricks). As a result, we have 128 * 2 = 256 bricks per 1 sq.m.
• It remains to multiply the volume of bricks in m2 by the number of m2 of masonry - 85.4x256 = 21,862.4 pcs.
• We multiply the result by the price of a brick, add the cost of delivery to the estimate.

The second calculation looks like this:

• Here, to complete the account, you will need to increase the estimated dimensions of the brick by 5 mm (standard thickness of the masonry joint). The calculations will look like this: (0.12+0.005)*(0.065+0.005)=0.00875. That is, the number of bricks in m2 will be: 1 / 0.00875 * 2 = 229 pcs. It remains to multiply the masonry area by the number of blocks in m2 - 229 * 100.6 = 23037.4 pcs. And it is necessary to add to the quantity a stock within 1500-2000 pcs. Approximately we have 25 thousand pieces of blocks. We also multiply the total by the price.
• It is worth noting that in order to display the cost of the walls, the solution must also be taken into account. According to building codes, it takes about 200 liters or 0.222 m3 per m2 of masonry in two bricks.

Important: a hollow brick will take more cement, as its voids will be filled with mortar. And this means overspending the mixture.

Roof estimate

It is easy to calculate costs here. Knowing the parameters of the roof from the design documentation, we derive the volume of the roofing material and multiply it by the price per unit volume. In the same way, we calculate the volume of waterproofing and insulation. The estimate includes lumber for the installation of rafters and battens, as well as all fasteners. The rental of special equipment for laying the ceiling and the cost of the work of the craftsmen should also be included in the documentation.

In total, we have a rough idea of ​​​​how to draw up a plan for expenses and construction costs.